Here is an example of Assembly Language code for 8086. This example illustrates how the addition of two 16 bit numbers using Direct Addressing Mode is done.
CODE SEGMENT // start of the logical code segment
ASSUME CS:CODE // this instruction will inform
the assembler the assumed name of CS. START: MOV AL, 99H // this instruction will move
the operand 99H to the accumulator.
MOV BL, 90H // this instruction will move
the operand 90H to the Register B.
ADC AL, BL // this instruction will add the
content of the Register B with the
content of the accumulator, the result
would be stored in AL and the carry
bit would be stored in AH.
MOV [2035H], AL // the result would be moved to
the memory location 2035H.
CODE ENDS // end of the logical code segment
CODE SEGMENT // start of the logical code segment
ASSUME CS:CODE // this instruction will inform
the assembler the assumed name of CS. START: MOV AL, 99H // this instruction will move
the operand 99H to the accumulator.
MOV BL, 90H // this instruction will move
the operand 90H to the Register B.
ADC AL, BL // this instruction will add the
content of the Register B with the
content of the accumulator, the result
would be stored in AL and the carry
bit would be stored in AH.
MOV [2035H], AL // the result would be moved to
the memory location 2035H.
CODE ENDS // end of the logical code segment
END START // end of the program
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