Here is an example of Assembly Language code for 8086. This example illustrates how the largest of two 8-bit number using Direct Addressing Mode is done.
CODE SEGMENT // start of the logical code segment
ASSUME CS:CODE // this instruction will inform
the assembler the assumed name of CS. START: MOV AL, 09H // this instruction will move the operand 09H to the accumulator.
MOV BL, 03H // this instruction will move
the operand 03H to the Register B.
CMP AL, BL // this instruction will compare the
content of the Register B with the
content of the accumulator, by the
means of subtraction.
JNC NEXT // this instruction will cause a jump
to the next label if no carry is
generated.
MOV [2035H], BL // if carry is generated the result from
Register B would be moved to the
memory location 2035H.
NEXT: MOV [2035H], AL // if carry is not generated the result
from accumulator would be moved
to the memory location 2035H.
CODE ENDS // end of the logical code segment
CODE SEGMENT // start of the logical code segment
ASSUME CS:CODE // this instruction will inform
the assembler the assumed name of CS. START: MOV AL, 09H // this instruction will move the operand 09H to the accumulator.
MOV BL, 03H // this instruction will move
the operand 03H to the Register B.
CMP AL, BL // this instruction will compare the
content of the Register B with the
content of the accumulator, by the
means of subtraction.
JNC NEXT // this instruction will cause a jump
to the next label if no carry is
generated.
MOV [2035H], BL // if carry is generated the result from
Register B would be moved to the
memory location 2035H.
NEXT: MOV [2035H], AL // if carry is not generated the result
from accumulator would be moved
to the memory location 2035H.
CODE ENDS // end of the logical code segment
END START // end of the program
NOTE:
While actually implementing this code the keyword next should be replaced with the address of the instruction.
NOTE:
While actually implementing this code the keyword next should be replaced with the address of the instruction.
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